The products of ozonolysis of an alkene are ethanal and methanal, then that alkene is

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${CH}_{3} - C \equiv C - {CH}_{3}$

${CH}_{3} - C = C - {CH}_{3}$

${CH}_{3} - CH = {CH}_{3}$

${CH}_{3} - CH \equiv CH$

answer is C.

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Detailed Solution

Reaction Explanation:

Step 1: Ozonolysis - Propane (also known as propene or propylene) reacts with ozone (O3) to form an unstable intermediate called ozonide.

Step 2: Reductive Work-up - The ozonide is then treated with zinc (Zn) in the presence of water (H2O), which reduces the ozonide and cleaves it into two carbonyl compounds.

Products:Ethanal (Acetaldehyde): CH3CHO - An aldehyde with two carbon atoms Methanal

(Formaldehyde): HCHO - An aldehyde with one carbon atom

Overall Reaction: This is an ozonolysis reaction, which is used to cleave carbon-carbon double bonds. The double bond in propene is broken, and oxygen atoms are added to form two separate carbonyl compounds.

Note: The original compound name shown as "Propane" in the image should technically be "Propene" or "Propylene" (CH3CH═CH2), as propane (CH3CH2CH3) is a saturated hydrocarbon without a double bond.