The projectile motion of a particle of mass 5 g is shown in the figure.
The initial velocity of the particle is $5 \sqrt{2} m s^{- 1}$ and the air resistance is assumed to be negligible. The magnitude of the change in momentum between the points A and B is $x \times 10^{- 2} k g m s^{- 1} .$ The value of x, to the nearest integer , is______

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Between ‘A’ and ‘B’, horizontal component of momentum remains same.

Vertical component of momentum charges from $m u \sin 45^{0}$ to $- m u \sin 45^{0}$
So, charge in momentum is
$Δ p = 2 m u \sin 45^{0} = (2) (5) (10^{- 3}) (5 \sqrt{2}) \frac{1}{\sqrt{2}}$

$Δ p = 5 \times 10^{- 2} K g - m / s$

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE