The projectile motion of a particle of mass 5 g is shown in the figure.

The initial velocity of the particle is $5 \sqrt{2} m s^{- 1}$ and the air resistance is assumed to be negligible. The magnitude of the change in momentum between the points A and B is $x \times 10^{- 2} k g m s^{- 1} .$ The value of x, to the nearest integer , is______

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answer is 5.

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Detailed Solution

Between ‘A’ and ‘B’, horizontal component of momentum remains same. Vertical component of momentum charges from $m u \sin 45^{0}$ to $- m u \sin 45^{0}$
So, charge in momentum is
$Δ p = 2 m u \sin 45^{0} = (2) (5) (10^{- 3}) (5 \sqrt{2}) \frac{1}{\sqrt{2}}$ $Δ p = 5 \times 10^{- 2} K g - m / s$

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