Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

 The projection of the line x+1-1=y2=z-13 on the plane x-2y+z=6 is the line of intersection of this plane with the plane 

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

2 x+y+2=0

b

3 x+y-z=0

c

2 x-3 y+8 z=3

d

None of these

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

 Given line x+1-1=y2=z-13

 And plane is x-2y+z=6

 Equation of the plane through 

(-1,0,1) is a(x+1)+b(y-0)+c(z-1)=0.(1)

 Which is parallel to the given line and perpendicular to the given plane 

-a+2 b+3 c=0

 and a-2b+c=0

c=0,a=2b

∴ From (1) equation of the required plane is 2x+y+2=0

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon