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Q.

The P.V.'s of the vertices of a ABC are i+j+k, 4i+j+k, 4i+5j+k, The P.V of the circumcentre of  ABC is

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a

52i+3j+k

b

5i+32j+k

c

5i+3j+12k

d

i+j+k

answer is A.

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Detailed Solution

OA=i+j+k , OB=4i+j+k , OC=4i+5j+k AB=3i  AB=3  AC=3i+4j BC=4j  BC=4  AC=5 ABC is right angle at B circum centre is a mid point of a,c      =5i+6j+2k2

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