The P.V.'s of A, B are a, b respectively. The P.V. of 'C' is 3a4+b2 then 'C' lies

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The P.V.'s of $A, B$ are $a, b$ respectively. The P.V. of $' C'$ is $\frac{3 a}{4} + \frac{b}{2}$ then 'C' lies

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inside $∆ OAB$

outside $∆ OAB$ but inside $∠ OAB$

outside $∆ OAB$ but inside $∠ AOB$

outside $∆ OAB$ but inside $∠ OBA$

answer is B.

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Detailed Solution

$c = \frac{5}{3} a - b p = \frac{5}{3} q = - 14 cisontficle the ∆ OAB but in side angle OBA$

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