The quadratic equation whose roots are $' l' and' m'$ where $l = \underset{θ \to 0}{L t} \frac{3 \sin θ - 4 \sin^{3} θ}{θ} and m = \frac{2 \tan θ}{θ (1 - \tan^{2} θ)}$ is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$x^{2} - 5 x - 6 = 0$

$x^{2} - 5 x + 6 = 0$

$x^{2} + 5 x + 6 = 0$

$x^{2} + 5 x - 6 = 0$

answer is B.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$l = \underset{θ \to 0}{L t} \frac{3 \sin θ - 4 \sin^{3} θ}{θ} = \underset{θ \to 0}{L t} \frac{\sin 3 θ}{θ} = 3$

$m = \underset{θ \to 0}{L t} \frac{2 \tan θ}{θ (1 - \tan^{2} θ)} = \underset{θ \to 0}{L t} \frac{\tan 2 θ}{θ} = 2$

Q.E is $x^{2} - (l + m) x + l m = 0$

$x^{2} - 5 x + 6 = 0$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test