The quadratic equation whose roots are 'l' and 'm' where l=Ltθ→0 3sinθ−4sin3θθ and m=2tanθθ(1−tan2θ) is

l=Ltθ→0 3sinθ−4sin3θθ=Ltθ→0sin3θθ=3m=Ltθ→02tanθθ(1−tan2θ)=Ltθ→0tan2θθ=2Q.E is x2−(l+m)x+lm=0x2−5x+6=0

The quadratic equation whose roots are 'l' and 'm' where l=Ltθ→0 3sinθ−4sin3θθ and m=2tanθθ(1−tan2θ) is

l=Ltθ→0 3sinθ−4sin3θθ=Ltθ→0sin3θθ=3m=Ltθ→02tanθθ(1−tan2θ)=Ltθ→0tan2θθ=2Q.E is x2−(l+m)x+lm=0x2−5x+6=0

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The quadratic equation whose roots are $' l' and' m'$ where $l = \underset{θ \to 0}{L t} \frac{3 \sin θ - 4 \sin^{3} θ}{θ} and m = \frac{2 \tan θ}{θ (1 - \tan^{2} θ)}$ is

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$x^{2} - 5 x - 6 = 0$

$x^{2} - 5 x + 6 = 0$

$x^{2} + 5 x + 6 = 0$

$x^{2} + 5 x - 6 = 0$

answer is B.

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$l = \underset{θ \to 0}{L t} \frac{3 \sin θ - 4 \sin^{3} θ}{θ} = \underset{θ \to 0}{L t} \frac{\sin 3 θ}{θ} = 3$

$m = \underset{θ \to 0}{L t} \frac{2 \tan θ}{θ (1 - \tan^{2} θ)} = \underset{θ \to 0}{L t} \frac{\tan 2 θ}{θ} = 2$

Q.E is $x^{2} - (l + m) x + l m = 0$

$x^{2} - 5 x + 6 = 0$

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The quadratic equation whose roots are 'l' and 'm' where l=Ltθ→0 3sinθ−4sin3θθ and m=2tanθθ(1−tan2θ) is

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The quadratic equation whose roots are $' l' and' m'$ where $l = \underset{θ \to 0}{L t} \frac{3 \sin θ - 4 \sin^{3} θ}{θ} and m = \frac{2 \tan θ}{θ (1 - \tan^{2} θ)}$ is