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The quadratic equation whose roots are $l + m, l - m$ , is

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x^{2} - 2 l x + l^{2} + m^{2} = 0

x^{2} + 2 l x + l^{2} - m^{2} = 0

x^{2} - 2 l x + l^{2} - m^{2} = 0

x^{2} - 2 m x + m^{2} - l^{2} = 0

answer is C.

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Detailed Solution

Let

α = l + m, β = l - m

$α + β = l + m + l - m = 2 l$

$α β = (l + m) (l - m) = (l^{2} - m^{2})$

Then quadratic equation is

$x^{2} - (α + β) x + α β = 0$

$x^{2} - (2 l) x + (l^{2} - m^{2}) = 0$

$x^{2} - 2 l x + (l^{2} - m^{2}) = 0$

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