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The quantity of copper (II) oxide reacts with 2.80 litre of hydrogen at NTP is
$CuO + H_{2} \to Cu + H_{2} O$

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9.95 g

12.0 g

9.51 g

10.0 g

answer is B.

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Detailed Solution

$CuO + H_{2} \to Cu + H_{2} O$

$1 mole CuO = 1 mole H_{2}$

$79.5 g of CuO = 22.4 L of H_{2}$

$? = 2.8 L of H_{2} at NTP$

$79.5 g = 22.4 L$

$= \frac{79.5 \times 28}{22.4} = 9.9375 gm$

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