The quantity of electricity in Faradays required to reduce 1.23 gm of nitro benzene to aniline is

$Moles \left(n\right) of Nitrobenzene = \frac{ mass of Nitrobenzene }{Molecular mass of nitrobenzene}=\frac{1.23}{123}=0.01 mol$

From the equation , reduction of 1 mol of nitrobenzene requires 6 mol of electrons i.e., 6F

1 mol nitrobenzene = 6F 

for 0.01 mol nitrobenzene = = 0.06 F