The quantity of electricity required to liberate 112 ${\mathrm{cm}}^3$ of hydrogen at STP from acidified water is

This is the process of reduction and reduction is takes place at cathode.
Therefore, at cathode  $2{\mathrm{H}}^{+}+2{\mathrm{e}}^{-}\to {\mathrm{H}}_2$
It means that for the liberation of 22.4L${\mathrm{H}}_2$ gas 2F is required
Also we know that 1000cc = 1L therefore for 112cc it is 0.112L
Again we know that 1mol=22.4L and for 22.4L ,charge is 193000c (because 1F=96500 C)
So, for  $0.112\mathrm{L}=\frac{193000\times 0.112}{22.4}=965\mathrm{C}$

Hence option A is correct.