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The quantity of heat developed in $15 Ω$ resistor in 2 minutes is

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600 J

1200 J

7200 J

3600 J

answer is C.

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Detailed Solution

$\begin{array}{l} 15 i = 30 (3 - i) \\ 3 i = 6 \\ i = 6 - 2 i \end{array}$

$\begin{array}{l} i = 2 A \\ Q = i^{2} Rt \\ = 4 \times 15 \times 2 \times 60 \\ = 4 \times 30 \times 60 \\ = 7200 J \end{array}$

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