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The quantum number of four electrons are
given below
I. n = 4; l = 2; m_l = –2; m_s = –1/2
II. n = 3; l = 2; m_l = 1; m_s= 1/2
III. n = 4; l = 1; m_l = 0; m_s = 1/2
IV. n = 3; l = 1; m_l = 1; m_s = –1/2
Order of their increasing energies will be

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IV > III > II > I

I > II > III > IV

I > III > II > IV

IV > II > III > I

answer is C.

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Detailed Solution

n=4 ,l=2 is 4d orbital

n=3 ,l=2 is 3d orbital

n=4 ,l=1 is 4p orbital

n=3 ,l=1 is 3p orbital

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