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Q.

The quantum numbers of four electrons e1 to e4 are given below:

Electronnlms
e1300+12
e2400-12
e3322-12
e431-1+12

The correct order of decreasing energy of these electrons is :

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a

e3> e2> e4> e1 

b

e1> e4> e2> e3

c

e4> e3> e2> e1 

d

e2> e3> e4> e1 

answer is C.

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Detailed Solution

According to n+l rule higher the n+l value higher is the energy.

If n+l value is same higher the value of "n" higher is the energy

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