The quantum numbers of four electrons (e1 to e4) are given below :

$\begin{array}{ccccr} & \mathit{n}& \mathit{l}& \mathit{m}& \mathit{s}\\ e1& 3& 0& 0& +\frac{1}{2}\\ e2& 4& 0& 0& \frac{1}{2}\\ e3& 3& 2& 2& -\frac{1}{2}\\ e4& 3& 1& -1& \frac{1}{2}\end{array}$

The correct order of decreasing energy of these electrons is:

the energy formula for electron in quantum number  is $\propto (n+1)$ value

$\begin{array}{r}\mathrm{e}1=3+0=3\\ \mathrm{e}2=4+0=4\\ \mathrm{e}3=3+2=5\\ \mathrm{e}4=3+1=4\end{array}$

If $(\mathrm{n}+1)$ value is same, then larger n value has more energy. 

so, 

correct order of decreasing energy of the electrons is $e3>e2>e4>e1$.