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The radioisotope $_{15} P^{32}$ is used in biochemical studies. A sample of this isotope has an activity 1000 times the detectable limit. How long could an experiment be run with the sample before the radioactivity could no longer be detected $(t_{1 / 2} = 14.2$ days)

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28 days

102 days

142 days

50 days

answer is C.

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Detailed Solution

$\frac{1}{1000} = e^{- \frac{114}{14.8} \times t} \Rightarrow t = 142 days$

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