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Q.

The radius of a circular plate is increasing at the rate of 0.01 cm/sec. When the radius is 12 cm, the rate at which the area increases is (in square cm/sec)

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a

24π

b

60π

c

0.24π

d

1.2π

answer is D.

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Detailed Solution

drdt=0.01  cm/s  , when   r=12cm , then  dAdt=?
 A=πr2     dAdt=2πrdrdt
    dAdt=2π(12)(0.01)   24100π  0.24π

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