The radius of a proton at the centre is $1.5 x 10^{- 5}$ m while the radius of H-atom is $5.32 x 10^{- 11}$ m. The ratio of radius of H-atom to the radius of proton is:

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$3.5 \times 10^{- 6}$

$3.5467 \times 10^{- 6}$

$3.54 \times 10^{- 6}$

$3.546 \times 10^{- 6}$

answer is D.

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Detailed Solution

$Ratio = \frac{Radius of H-atom}{Radius of Proton} = \frac{5.32 \times 10^{- 11} m}{1.5 \times 10^{- 5} m}$

$3.546 \times 10^{- 6}$ . In division, the number of significant figures in the final answer should not be greater than the number of significant figures in the least precise factor. The least number of significant figures $= 2 (i.e., in 1.5 \times 10^{- 5})$ . So, the correct answer is $3.5 \times 10^{- 6}$ i.e.,