The radius of a roller is 0.7 m and it is 2 m long. Then the area covered by it in 10 revolutions is

Given radius$\left(r\right)=0.7\mathrm{m}$

Height $\left(h\right)=2m$

Curved surface area of cylinder (roller)$=2\pi rh$$=2\times \frac{22}{7}\times \frac{7}{10}\times 2=\frac{44}{5}{\mathrm{m}}^2$

Area covered in 10 revolutions$=10\times \frac{44}{5}$

$=88{\mathrm{m}}^{2}7$