The radius of a wire is decreased to one-third. If volume remains the same, length will increase by

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The radius of a wire is decreased to one-third. If volume remains the same, length will increase by

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3 times

9 times

6 times

1.5 times

answer is D.

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Detailed Solution

According to question,

$π r^{2} h = π \times {(\frac{1}{3} r)}^{2} \times H = \frac{π r^{2} H}{9} \Rightarrow H = 9 h$

So, length will increased by 9 times.

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