The radius of an atom of an element is 80 pm. If it crystallises as a body centred cubic lattice, what is the edge of its unit cell?

The relationship between the edge length a and the radius r for a body-centered cubic lattice is as follows: $a=\frac{4r}{\sqrt{3}}$

When values are substituted in the expression above, we obtain
$\mathrm{a}=\frac{4\times 80}{\sqrt{3}}=184.7\mathrm{pm}$

Therefore, the correct option is B 184.7pm