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Q.

The radius of fifth orbit of the ${Li}^{+ +} is ____\times 10^{- 12} m .$
Take : Radius of hydrogen atom $= 0.51 \overset{0}{A}$

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answer is 425.

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Detailed Solution

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$r_{n} = 0.51 \times \frac{n^{2}}{Z} = 0.51 \times \frac{25}{3} \times 10^{- 10} = 4.25 \times 10^{- 10} m$

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