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Q.

The radius of first half period zone is 0.05 cm and λ = 5000Å. The distance between slit and screen is

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a

0.0005 m

b

0.05 m

c

0.5 m

d

0.005 m

answer is A.

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Detailed Solution

r=bnλ;b=r2nλ=25×10−85×10−7=5×10−1=0.5m

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