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The radius of first orbit of hydrogen is 0.53 Å. The radius of second orbit would be:

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$1.06 Å$

$0.26 Å$

$0.53 Å$

$2.12 Å$

answer is D.

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Detailed Solution

$\begin{array}{l} r_{n}^{} = 0.53 \times n^{2} \\ ∴ r_{2}^{} = 0.53 \times 4 = 2.12 \overset{0}{A} \end{array}$

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