The radius of germanium (Ge) nuclide is measured to be twice the radius of $_{4}^{9} Be$ . The number of nucleons in Ge are

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answer is C.

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Detailed Solution

We use the formula,

$R = R_{0} A^{\frac{1}{3}}$

For $B e$ , $R_{1} = R_{0} (9)^{1 / 3}$

For $G e$ , $R_{2} = R_{0} A^{1 / 3}$

$\begin{array}{l} \frac{R_{1}}{R_{2}} = \frac{(9)^{\frac{1}{3}}}{(A)^{\frac{1}{3}}} = \frac{1}{2} \\ \Rightarrow \frac{1}{8} = \frac{9}{A} \Rightarrow A = 8 \times 9 = 72 . \end{array}$

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