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Q.

The radius of gyration of solid hemisphere of mass M and radius R about an axis parallel to the diameter at a distance 3R / 4 from center and lying in the same plane is given by (center of mass of the hemisphere of the hemisphere lies at a height 3R / 8  from the base)

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a

3R10

b

5R4

c

25R

d

5R8

answer is D.

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Detailed Solution

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IXX'=25MR2

The axes PQ and XX' are at an equal distance from center of mass of the hemisphere

⇒IPQ=IXX'

MK2=25MR2⇒K=25R

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