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The radius of hydrogen atom in ground state is $0 .53 Å$ What will be the radius of $_{3} {Li}^{2 +}$ in the ground state?

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$1 .06 Å$

$0 .265 Å$

$0 .176 Å$

$0 .53 Å$

answer is C.

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Detailed Solution

Radius of n^th orbit is given by r_n $= \frac{r_{0} \times n^{2}}{Z}$ For $_{3} {Li}^{2 +}, r = \frac{r_{0}}{3} = \frac{0 .53}{3} = 0 .176 Å$

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