The radius of nucleus of silver (atomic number = 47) is 3.4×10−14m. The electric potential on the surface of nucleus is (e=1.6×10−19C)

V=14πε0⋅(Ze)r=9×109×47×1.6×10−193.4×10−14=1.99×106V

The radius of nucleus of silver (atomic number = 47) is 3.4×10−14m. The electric potential on the surface of nucleus is (e=1.6×10−19C)

V=14πε0⋅(Ze)r=9×109×47×1.6×10−193.4×10−14=1.99×106V

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The radius of nucleus of silver (atomic number = 47) is $3 .4 \times 10^{- 14} m$ . The electric potential on the surface of nucleus is $(e = 1 .6 \times 10^{- 19} C)$

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$V = \frac{1}{4 {πε}_{0}} \cdot \frac{(Ze)}{r} = 9 \times 10^{9} \times \frac{47 \times 1 .6 \times 10^{- 19}}{3 .4 \times 10^{- 14}} = 1 .99 \times 10^{6} V$

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The radius of nucleus of silver (atomic number = 47) is 3.4×10−14m. The electric potential on the surface of nucleus is (e=1.6×10−19C)

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The radius of nucleus of silver (atomic number = 47) is $3 .4 \times 10^{- 14} m$ . The electric potential on the surface of nucleus is $(e = 1 .6 \times 10^{- 19} C)$