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The radius of the circle in which a central angle of $60 °$ intercepts an arc of length $37.4 c m$ is $(Use π = \frac{22}{7})$

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$37.5 c m$

$32.8 c m$

$35.7 c m$

$34.5 c m$

answer is C.

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Detailed Solution

Here, $l = 37.4 c m$ and $θ = 60^{\circ} = \frac{60 π}{180} radian = \frac{π}{3}$

Hence, by $r = \frac{l}{θ},$ we have

$r = \frac{37.4 \times 3}{π} = \frac{37.4 \times 3 \times 7}{22} = 35.7 cm .$

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