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The radius of the curved road on a national highway is R. The width of the road is $b$ . The outer edge of the road is raised by h with respect to the inner edge, so that a car with velocity $v$ can pass safe over it. The value of $h$ is

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$\frac{v}{Rgb}$

$\frac{v^{2} b}{Rg}$

$\frac{v^{2} R}{g}$

$\frac{u^{2} b}{R}$

answer is A.

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Detailed Solution

$tanθ = \frac{h}{b} = \frac{v^{2}}{Rg}$

$\Rightarrow h = \frac{v^{2} b}{Rg}$

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