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The radius of the orbital of electron in the hydrogen atom 0.5 $A^{0}$ . The speed of the electron is 2 x $10^{6}$ m/s. Then the current in the loop due to the motion of the electron is

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1.5 x $10^{- 2}$ mA

1 mA

1.5 mA

2.5 mA

answer is A.

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Detailed Solution

Time period of revolution of electron $T = \frac{2 π}{ω} = \frac{2 πr}{v}$

Hence corresponding electric current $i = \frac{e}{T} = \frac{e v}{2 π r}$

$\Rightarrow i = \frac{1 .6 \times 10^{- 19} \times 2 \times 10^{6}}{2 \times 3 .14 \times 0 .5 \times 10^{- 10}} = 1 mA$

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