Q.

The radius of water molecule having density 1g mL-1 is

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a

19.25 Ao

b

1.925 Ao

c

73.46 Ao

d

7.346 Ao

answer is A.

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Detailed Solution

.Volume of 1gm water molecules= 1cm3

Volume of 181​ mole of water= 10−6m3

181​ mole of water= 6.023×1023×181​ molecules of water

Volume of 181​×6.023×1023 molecules= 10−6m3

Hence, Volume of one water molecule= 0.2988×10−28m3

Let. the radius of water molecule be r

0.2988×10−28=34​×π×r3

r=0.1925 nm=1.925A˚

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