Q.

The radius of which of the following orbit is same as that of the first Bohr's orbit of hydrogen atom?

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a

Li2+ (n = 2)

b

He+ (n = 2)

c

Be3+ (n = 2)

d

Li2+ (n = 3)

answer is D.

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Detailed Solution

 First Bohr's orbit of hydrogen atom is  0.529 ×n2 /Z A0 =0.529 A0

(A) The radius of He+ (n = 2) =0.529 ×n2 /Z  A0 =0.529 × 222A0 =1.058A0

(B)The radius of Li2+ (n = 2) =0.529 ×n2 /Z  A0 =0.529 ×322A0 =0.705 A0

(C)The radius of Li2+ (n = 3) = 0.529 ×n2 /Z  A0 =0.529 ×323A0 =1.587 A0

(D)The radius of Be3+ (n = 2) =0.529 ×n2 /Z  A0 =0.529 ×224A0 = 0.529 A0

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