The radius R of a nucleus of mass number A can be estimated by the formula $R = (1.3 \times 10^{- 15}) A^{1 / 3} m$ . It follows that the mass density of a nucleus is of the order of : $(M_{prot} ≅ M_{neut} = 1.67 \times 10^{- 27} kg)$

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$10^{17} k g m^{- 3}$

$10^{24} k g m^{- 3}$

$10^{10} k g m^{- 3}$

$10^{3} k g m^{- 3}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$d e n s i t y = \frac{M_{P}}{V_{P}}$

$\begin{array}{l} = \frac{1.67 \times 10^{- 27} \times A}{\frac{4}{3} π {(1.3 \times 10^{- 15})}^{3} (A)} kg / m^{3} \\ = \frac{3 \times 1.67}{4 π \times (1.3)^{3}} \times 10^{18} kg / m^{3} \\ = \frac{30 \times 1.67}{4 π (1.3)^{3}} \times 10^{17} kg / m^{3} \\ ∴ d = 1.81 \times 10^{17} kg / m^{3} \end{array}$