The range of the function f(x)=−−x2−6x−5 is

y=−−x2−6x−5=-x2-6x-5 =-x2+6x+5 =4-x2+6x+9 y=4-x+32Range is −2, 0

y=−−x2−6x−5=-x2-6x-5 =-x2+6x+5 =4-x2+6x+9 y=4-x+32Range is −2, 0

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Offline Centres

The range of the function $f (x) = - \sqrt{- x^{2} - 6 x - 5}$ is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$[\begin{array}{l} - 2, 0 \end{array}]$

$(- \infty, 2]$

$[0, 2]$

$[- 2, 2]$

answer is B.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

$y = - \sqrt{- x^{2} - 6 x - 5}$

$= - x^{2} - 6 x - 5 = - [x^{2} + 6 x + 5] = 4 - [x^{2} + 6 x + 9] y = \sqrt{4 - {(x + 3)}^{2}}$

Range is $[\begin{array}{l} - 2, 0 \end{array}]$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test