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 The range of cosx+42sinxπ4+6 is 

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a
[1,11]
b
[1,11]
c
[2,10]
d
[10,11]

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detailed solution

Correct option is A

f(x)=cosx+42sinxπ4+6 f(x)=cosx+42sinxcosπ4-cosxsinπ4+6 f(x)=cosx+42sinx-cosx2+6 f(x)=cosx+4sinx-cosx+6 f(x)=4sinx-3cosx+6 Range=6-16+9,6+16+9=6-5,6+5=1,11

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