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Q.

The range of f(x)=-x3+x2-x+cos-1 x is

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a

[-1,π]

b

[-1,3+π]

c

[0,π-1]

d

[-1,2+π]

answer is A.

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Detailed Solution

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f(x)=-x3+x2-x+cos-1 x

Domain of f(x)=[-1,1]  f'(x)=-3x2+2x-1-11-x2<0

'f ' is a decreasing function

  Min of f (x) is f(1)=-1+1-1+0=-1

Max of f (x) is f(-1)=1+1+1+π=3+π

Range=-1,3+π

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