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Q.

The rate constant for a reaction of zero order in A is 0.0030 mol L-1 s-1. How long will it take for the initial concentration of A to fall from 0.10 M to 0.075 M?

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Detailed Solution

For a zero order reaction,
Time, $t = \frac{1}{K} [(A)_{0} - (A)]$
or $t = \frac{1}{0 .003} (0 .10 - 0 .075)$
$∴$ Time, $t = \frac{1}{0 .003} \times \frac{0 .025}{1} = \frac{25}{3} = 8 .3 seconds$

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