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Q.

The rate constant for the reaction $A ⟶ B$ is 2 x 10^-4 L mol^-1 min^-1. The concentration of A at which rate of the reaction is $(\frac{1}{12}) \times 10^{- 5} M \sec^{- 1}$ is :

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a

0.25 M

b

0.5 M

c

none of these

d

$(\frac{1}{20}) \sqrt{\frac{5}{3}} M$

answer is C.

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Detailed Solution

Here, the rate of the reaction,

$\begin{array}{l} r = k [A]^{2} \\ \frac{1}{12} \times 10^{- 5} = \frac{2 \times 10^{- 4}}{60} \times [A]^{2} \\ [A] = 0.5 M \end{array}$

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