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The rate constant of a first order reaction at $27^{0} C$ is $10^{- 3} \min^{- 1}$ . The 'temperature coefficient' of this reaction is 2. What is the rate constant (in $\min^{- 1}$ ) at $17^{0} C$ for this reaction?

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$10^{- 3}$

$5 \times 10^{- 4}$

$2 \times 10^{- 3}$

$10^{- 2}$

answer is B.

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Detailed Solution

$temperature co-effecient = 2$

$∴ At 27^{0} C \to K = 10^{- 3} \min^{- 1}$

$a t 17^{0} C \to K = \frac{10^{- 3}}{2} = 5 \times 10^{- 4} \min^{- 1}$

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