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Q.

The rate constant of a reaction increases by five times on increase in temperature from  270C  to  520C . The value of activation energy in kJ mol-1 is____ (rounded-off to the nearest integer). [R=8.314 J K-1mol-1]

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answer is 52.

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Detailed Solution

T1=300K,T2=325K,K2=5K,

lnK2K1=EaR1T11T2 or, ln5=Ea8.31413001325 or, Ea=0.7×2.303×8.314×12×325=52271J=52.271kJ

Nearest integer answer will be 52 kJ

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