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Q.

The rate constant of a reaction is  1.5'10-7S-1  at 50°C and 4.5' 10-7 S-1 at 100°C .The value of energy of activation is

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a

2.2' 10-4J mol-1

b

1.1' 103J mol-1

c

103J mol-1

d

3.3' 104J mol-1

answer is A.

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Detailed Solution

logK2K1=Ea2.303T2-T1T1T2

Log4.5×10-71.5×10-7=Ea2.303×8.314373-323323×373

log 3=Ea2.303×8.31450323×373

0.4771=Ea2.303×8.314×50323×373

and then,Ea=0.4771×2.303×8.314×323×37350Ea=2.2×10-4J mol-1

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