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Q.

The rate constant, the activation energy and the frequency factor of a chemical reaction at 25° C are 3.0×10−4s−1,104.4k J mol−1 and 6.0×1014g−1 respectively

The value of the rate constant as T⟶∞ is :

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a

6.0×1014s−1

b

3.6×1030s−1

c

2.0×1018s−1

d

infinite

answer is B.

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Detailed Solution

Given

Rate constant K=3.0×10−4s−1

Activation energy Ea=104.4k J mol−1

Frequency factor A=6.0×1014g−1 

The value of the rate constant as T⟶∞ is :

limT→∞ k=A

=6.0×1014s−1

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