Q.

The rate constant K1 of a reaction is found to be double that of rate constant K2 of another reaction. The relationship between corresponding activation energies of the two reactions E1 and E2 can be represented as

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

E1=E2

b

E1=2E2

c

E1>E2

d

E1<E2

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

As we are aware, the Arrhenius equation is expressed as the equation:

                 k=Ae-EaRT

It is discovered that the reaction's rate constant drops as the activation energy rises. It is discovered that the rate constant of the first reaction is two times greater than the rate constant of the second reaction. As a result, the first reaction's activation energy is lower than the second reaction's, which is represented by the expression:

                E1<E2

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon