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The rate equation for a reaction, $A \to B$ is $r = k (A) ° .$ If the initial concentration of the reactant is a $mol {dm}^{- 3},$ the half-period of the reaction is:

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$k / 2$

$a / k$

$2 a / k$

$a / 2 k$

answer is D.

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Detailed Solution

Given: rate $= k [A] ° .$ So order of reaction is zero. For a zero order reaction, $t_{1 / 2} \propto a$

$∴ t_{1 / 2} = \frac{a}{2 k} .$

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