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Q.

The rate equation for the gaseous phase reaction 2 AB + B2  2 AB2, is observed to be

 Rate =k[AB]2B2

Possible mechanism(s) consistent with this rate equation is/are:

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a

2AB+B2 slow 2AB2

b

AB+ABA2B2( fast equilibrium step) A2B2+B2 slow 2AB2

c

AB+B2 slow AB3AB+AB3 fast 2AB2

d

AB+B2AB3 (fast equilibrium step) AB+AB3 slow 2AB2

answer is A, B, D.

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Detailed Solution

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In mechanism each step is elementary whose rate law can be written directly from stoichiometric coefficients of reactants. Rate of reaction = rate of slowest step.
Rate law should not contain concentration of intermediate. It
may contain concentration of reactant, product and catalyst.

1. Rate = k[AB]2 [B2]

2. Rate = rate of slowest step = kB2A2B2=kB2Ke[AB][AB]=k[AB]2B2

3.  Rate =k[AB]B2

4. Rate = rate of slowest step = k[AB]AB3=k[AB]Keq[AB]B2=k[AB]2B2

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The rate equation for the gaseous phase reaction 2 AB + B2 → 2 AB2, is observed to be Rate =k[AB]2B2Possible mechanism(s) consistent with this rate equation is/are: