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The rate expression for the reaction A_(g) + B_(g) → C_(g), is rate = k[A]² [B]^1/2. What changes in the initial concentrations of A and B will cause the rate of reaction to increase by a factor of eight ?

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[A] = 2, [B] = 4

[A] = 1, [B] = 4

[A] = 4, [B] = 1

[A] = 2, [B] = 2

answer is B.

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Detailed Solution

If [A'] = 2[A], [B'] = 4[B]
Rate = $k {[A^{'}]}^{2} {[B^{'}]}^{1 / 2} = K [2 A]^{2} [4 B]^{1 / 2} = k [A]^{2} [B]^{1 / 2} \times 8$

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