The rate law for inversion of cane sugar is R=k [C₁₂H₂₂O₁₁][H₂O]. Find the concentration of sucrose if the rate of the reaction is 0.032 s^-1 and rate constant k=0.005.

Given, rate constant k=0.005, rate of the reaction R=0.032 s^-1.
Inversion of cane sugar is a pseudo first order reaction and water is present in large excess so the rate law becomes 

R=k [C₁₂H₂₂O₁₁]
0.032 = 0.005  [C₁₂H₂₂O₁₁]
[C₁₂H₂₂O₁₁] =6.4 M