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The rate law for the reaction : $RCl + NaOH \to ROH + NaCl$ .is given by : rate = k [RCl]. The rate of this reaction

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is doubled by doubling the concentration of NaOH

is halved by reducing the concentration of RCl by one half

is increased by increasing the temperature of the reaction

is unaffected by change in temperature

answer is B, C.

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Detailed Solution

Since order with respect to RCl is one, rate is halved on reducing [RCl] to half. Rate of reaction increases with increase in temperature.

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