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Q.

The rate law of a reaction, A+B product is rate =K[A]n[B]m on doubling the concentration of A and halving the concentration of B, the ratio of new rate to the earlier rate of reaction will be

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a

2nm

b

12m+n

c

m+n

d

nm

answer is B.

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Detailed Solution

r1=K[A]n[B]mr2=K(2A)nB2m=2n2mK[A]n[B]m=2nmr1

 

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